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Code Issues Releases Wiki Activity

Don't show matches on showcase which are more than four days away

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This commit is contained in:
Dean Herbert 2018-11-18 21:15:29 +09:00
parent 5621101d40
commit 8fab241ce3
1 changed files with 3 additions and 2 deletions
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5
osu.Game.Tournament/Screens/Schedule/ScheduleScreen.cs
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@ -1,6 +1,7 @@
// Copyright (c) 2007-2018 ppy Pty Ltd <contact@ppy.sh>. // Copyright (c) 2007-2018 ppy Pty Ltd <contact@ppy.sh>.
// Licensed under the MIT Licence - https://raw.githubusercontent.com/ppy/osu/master/LICENCE // Licensed under the MIT Licence - https://raw.githubusercontent.com/ppy/osu/master/LICENCE
using System;
using System.Linq; using System.Linq;
using osu.Framework.Allocation; using osu.Framework.Allocation;
using osu.Framework.Configuration; using osu.Framework.Configuration;
@ -76,7 +77,7 @@ namespace osu.Game.Tournament.Screens.Schedule
RelativeSizeAxes = Axes.Both, RelativeSizeAxes = Axes.Both,
Width = 0.4f, Width = 0.4f,
ChildrenEnumerable = ladder.Pairings ChildrenEnumerable = ladder.Pairings
.Where(p => p.Completed.Value && p.Team1.Value != null && p.Team2.Value != null) .Where(p => p.Completed.Value && p.Team1.Value != null && p.Team2.Value != null && Math.Abs(p.Date.Value.DayOfYear - DateTimeOffset.UtcNow.DayOfYear) < 4)
.OrderByDescending(p => p.Date.Value) .OrderByDescending(p => p.Date.Value)
.Take(8) .Take(8)
.Select(p => new SchedulePairing(p)) .Select(p => new SchedulePairing(p))
@ -86,7 +87,7 @@ namespace osu.Game.Tournament.Screens.Schedule
RelativeSizeAxes = Axes.Both, RelativeSizeAxes = Axes.Both,
Width = 0.6f, Width = 0.6f,
ChildrenEnumerable = ladder.Pairings ChildrenEnumerable = ladder.Pairings
.Where(p => !p.Completed.Value && p.Team1.Value != null && p.Team2.Value != null) .Where(p => !p.Completed.Value && p.Team1.Value != null && p.Team2.Value != null && Math.Abs(p.Date.Value.DayOfYear - DateTimeOffset.UtcNow.DayOfYear) < 4)
.OrderBy(p => p.Date.Value) .OrderBy(p => p.Date.Value)
.Take(8) .Take(8)
.Select(p => new SchedulePairing(p)) .Select(p => new SchedulePairing(p))